Solve the system of equations y = - x + 2 y = x^2-6+8

Answer: x=6 and y = - 4 and x = - 1 and y=3

Step-by-step explanation:

Your two equations are y = - x + 2

and y=x^2 - 6x + 8

Subsituting y=-x+2, we get

-x + 2 = x^2 - 6x + 8

x^2 - 5x + 6 = 0

Solving by the quadratic formula gives,

(5+ / - sqrt (25+24)) / 2

Thus, the two solutions are 6, and - 1.

So x=6

y = - 4 and

x=-1

y = 3