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16 April, 11:32

P (x) = x4 - 9x2 - 4x 12? what some roots

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  1. 16 April, 11:44
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    P (x) = x^4 - 9x^2 - 4x + 12

    P (1) = 1^4 - 9 (1) ^2 - 4 (1) + 12 = 1 - 9 - 4 + 12 = 0

    x = 1 is a root.

    By dividing the polynomial by x - 1, gives other roots as 3 and - 2
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