Ask Question
15 April, 21:25

Evaluate the discriminant of each equation. Tell how many solutions each equation has and whether the solutions are real or imaginary

x^2 + 4x + 5 = 0

x^2 - 4x - 5 = 0

4x^2 + 20x + 25 = 0

+4
Answers (1)
  1. 15 April, 21:44
    0
    All these equations are in the form of ax^2 + bx + c = 0, where a, b, and c are some numbers. the discriminants of equations like this are equal to b^2 - 4ac. if the discriminant is negative, there are two imaginary solutions. if the discriminant is positive, there are two real solutions. if the discriminant is 0, there is one real solution.

    x^2 + 4x + 5 = 0

    b^2 - 4ac

    4^2 - 4 (1) (5)

    16-20

    -4, two imaginary solutions.

    x^2 - 4x - 5 = 0

    b^2 - 4ac

    (-4) ^2 - 4 (1) (-5)

    16 + 20

    36, two real solutions.

    4x^2 + 20x + 25 = 0

    b^2 - 4ac

    20^2 - 4 (4) (25)

    400 - 400

    0, one real solution.
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “Evaluate the discriminant of each equation. Tell how many solutions each equation has and whether the solutions are real or imaginary x^2 + ...” in 📗 Mathematics if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers