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26 March, 16:00

In a right triangle the length of a hypotenuse is c and the length of one leg is a, and the length of the other leg is b, what is the value of b, if

c=2b, a=12?

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Answers (2)
  1. 26 March, 16:13
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    u r smart
  2. 26 March, 16:20
    0
    b = 4√3

    using Pythagoras' identity in the given triangle

    c² = a² + b² (substitute c = 2b and a = 12 into the equation)

    (2b) ² = 12² + b²

    4b² = 144 + b² (subtract b² from both sides)

    4b² - b² = 144

    3b² = 144 (divide both sides by 3)

    b² = 48 (take the square root of both sides)

    b = √48 = √ (16 * 3) = √16 * √3 = 4√3 ' exact value '
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