Ask Question
18 December, 14:20

Miguel has 52 coins in dimes and nickels totaling $4.50. how many of each coin does he have?

+4
Answers (1)
  1. 18 December, 14:42
    0
    See what would happen if there was half and half (26 dimes and 26 nickels).

    26 (.05) + 26 (.1) = 1.3+2.6=3.9

    There needs to be more;

    There needs to be 14 nickels and 38 dimes.

    14 (.05) + 38 (.1) =.7+3.8=4.5
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “Miguel has 52 coins in dimes and nickels totaling $4.50. how many of each coin does he have? ...” in 📗 Mathematics if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers