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21 September, 13:32

Solve S=2ab+2bc+2ac for b

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  1. 21 September, 13:37
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    S = 2 (ab + bc + ac)

    (S/2) = ab + bc + ac

    (S/2) - ac = ab + bc

    (S/2) - ac = b (a+c)

    [ (S/2) - ac] / (a+c) = b

    b = [ (S/2) - ac] / (a+c)
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