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23 August, 13:10

The dimensions of a certain ibm machine are 20" x 17" x 48". if the size of the machine is increased proportionately until the sum of its dimensions equals 200", what will be the increase in the shortest side

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  1. 23 August, 13:24
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    The dimensions of the machine are 20,48 and 17. If each dimension is increased by a factor of x;

    Then new dimensions are

    20x, 48x and 17x

    The sum of the dimensions are;

    20x + 48x + 17x = 200

    85x = 200

    x = 200/85

    Therefore each dimension was increased by a factor of x,

    The new dimension of the shortest side is 17" * 200/85 = 40

    So the increase in the shortest side;

    40-17 = 23"
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