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2 February, 13:52

If 2x-3y=10. and xy=16 find the value of8x³-27y³

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  1. 2 February, 13:59
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    8x³-27y³=3880

    Step-by-step explanation:

    2x-3y=10

    xy=16

    8x³-27y³=?

    as we know that

    (a-b) ³=a³-b³-3ab (a-b)

    now we substitue the formula according to our question

    (2x-3y) ³ = (2x) ³ - (3y) ³-3 (2x) (3y) (2x-3y)

    (10) ³=8x³-27y³-18 (16) (10)

    1000=8x³-27y³-2880

    1000+2880=8x³-27y³

    3880=8x³-27y³
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