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29 October, 04:35

Find the vertex of y=x^2+6x-16

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  1. 29 October, 04:37
    0
    (-3,-25)

    Step-by-step explanation:

    x^2+6x-16

    = (x^2+6x+9) - 16-9

    = (x+3) ^2-25

    When a quadratic is written in the form y = a (x-h) ^2 + k, the vertex is (h, k).

    Vertex = (-3,-25)
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