On an avaredge day a horse might drink 50 mL, a sheep might drink 4 L and a chicken might drink 200 mL. How much water would a farm with 3 horses, 15 sheep, and 12 chickens need for a day?

1 horse → 5o mL

3 horses → 50 x 3 = 150 mL

1 sheep → 4L

15 sheep → 4 x 15 = 60 L - 60 000mL

1 chicken → 200 mL

12 chicken → 200 x 12 = 2400 mL

Total = 150 + 60 000 + 2400 = 62550mL or 62L and 550mL

Answer: 62L and 550mL