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Trevin Hays
Mathematics
26 January, 09:09
5y+2 (3y-1) = 1y - (y+2) =
+2
Answers (
1
)
Isis Nixon
26 January, 09:25
0
y=0
Step-by-step explanation:
5y+2 (3y-1) = 1y - (y+2)
Distribute
5y + 6y - 2 = y - y - 2
Combine like terms
11y - 2 = - 2
Add 2 to each side
11y - 2+2 = - 2+2
11y = 0
Divide by 11
11y/11 = 0/11
y = 0
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