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17 June, 21:46

If 49x2 + 28x - 10 is rewritten as p2 + 4p - 10, what is p in terms of

p=

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  1. 17 June, 21:57
    0
    p=7x

    Step-by-step explanation:

    49x^[2] + 28x - 10 = p^[2] + 4p - 10

    This equation is in the form a^[2]x + bx + c.

    The 'c' is common for both equations, this means the 'a' and 'b' must also be common.

    There are two ways to find p: 'a' or 'b'

    a method

    49x^[2] = p^[2]

    => The square root of both sides = 7x = p

    b method

    28x = 4p

    28x/4 = 4p/4

    7x = p
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