Sign In
Ask Question
Alexus Cook
Mathematics
26 January, 10:04
Let f (x) = 5x-7 find f (5)
+3
Answers (
1
)
Janae Daniel
26 January, 10:16
0
F (x) = 5x - 7
f (5) = 5 (5) - 7
f (5) = 25 - 7
f (5) = 18
Comment
Complaint
Link
Know the Answer?
Answer
Not Sure About the Answer?
Find an answer to your question 👍
“Let f (x) = 5x-7 find f (5) ...”
in 📗 Mathematics if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers
You Might be Interested in
Two buses leave towns 948 miles apart at the same time and travel toward each other. One bus travels 10 mi h slower than the other. If they meet in 6 hours, what is the rate of each bus?
Answers (1)
Which value for x makes the open sentence true? 5 + 4 • x = 32 + x2
Answers (1)
The first step in determining the solution to the system of equations, y = - x2 - 4x - 3 and y = 2x + 5, algebraically is to set the two equations equal as X? - 4x - 3 = 2x + 5. What is the next step? Set y = 0in y = - x? - 4x - 3.
Answers (1)
What is the gcf of the polynomial 9x-27y+9
Answers (1)
In a certain company, 30 percent of the men and 20 percent of the women attend night school. if 40 percent of all employees are men, what percent of all the employees attend night school?
Answers (1)
New Questions in Mathematics
Simplify the expression 4x^5y^3x3x^8y^7/6x^4y^10
Answers (1)
If you know the ratio of inches to centimeters is 1 to 2.54, how can you find the number of centimeters equivalent to 9 inches? What is the relationship between centimeters and inches?
Answers (2)
If f (x) = - 3x4 - 2x3 + 3x2, and g (x) = 3x4 - 4x3 + x2 then f (x) + g (x) = A. 2x3 - 2x2 B. - 6x3 + 4x2 C. - 3x4 - 6x3 + 4x2 D. 3x4 + 2x3 - 2x2
Answers (1)
How do i solve this 2x+y=2 - 2x-5y=14
Answers (2)
Using side lengths only, could the triangles be similar? Triangle X Y Z. Side X Y is 1.5, X Z is 1, Z Y is 2. Triangle Q S R. Side Q R is 1, R S is 1.5, S Q is 0.5.
Answers (1)
Home
»
Mathematics
» Let f (x) = 5x-7 find f (5)
Sign In
Sign Up
Forgot Password?