The widrh of a rectangle is w yards and the length of a rectangle is (6w-4) yards. The perimeter of the rectangle is given by the algebraic expression 2w+2 (6w-4). Simplify the algebraic expression 2w+2 (6w-4) and determine the perimeter of a rectangle whose width w is 4 yards

Question

Jadyn

Mathematics

5 August, 22:20

The widrh of a rectangle is w yards and the length of a rectangle is (6w-4) yards. The perimeter of the rectangle is given by the algebraic expression 2w+2 (6w-4). Simplify the algebraic expression 2w+2 (6w-4) and determine the perimeter of a rectangle whose width w is 4 yards

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Tristan Frost · Answer 1

p=2w+2 (6w-4) can be simplified to:

p=2w+12w-8

p=14w-8

if w=4

p=14 (4) - 8

p=56-8 = 48 yards

check:

w = 4

length = 6w-4 = 6 (4) - 4 = 24-4=20

perimeter = 4*2 + 20*2 = 8+40 = 48

it checks out, perimeter = 48 yards