X varies inversely as y^2, and x = 4 when y = 10. Find x when y = 2.

a. x = 5

b. x = 80

c. x = 100

X = k/y^2 is the equation for this statement

substitute the values for the first x and y to find k, the constant of variation.

4 = k/10^2

4 = k/100 Multiply by 100 to clear the fraction

400 = k

Now substitute the k back in and make a new equation that will find any value of x that fits this scenario

x = 400/y^2

x = 400/4

x = 100