3 (3y - 6) = 7y - 18 + Zy

The answer

Answer: y = 0/-z+2

Step-by-step explanation:

3 (3y-6) = 7y-18+zy

Step 1:

9y-18+-yz=yz+7y-18+-yz

-yz+9y-18=7y-18

Step 2:

-yz+9y-18+-7y=7y-18+-7y

-yz+2y-18=-18

Step 3:

-yz+2y-18+18=-18+18

-yz+2y=0

Step 4:

y (-z+2) = 0

Step 5:

y (-z+2)

-z+2

=

0 / -z+2

Z = 2

Step-by-step explanation:

First, distribute the terms on the left side of the equation.

3 (3y - 6) = 7y - 18 + Zy

9y-18=7y-18+Zy, Next add 18 to both sides

9y = 7y+Zy, Subtract 7y from both sides

2y = Zy, Divide both sides by y

2 = Z, Z=2