The sum of 6 consecutive integers is 519. What is the third number in this sequence?

6 consecutive integers

x, x+1, x+2, x+3, x+4, x+5

sum of 6 consecutive integers is 519

x + x+1 + x+2 + x+3 + x+4 + x+5 = 519

6x + 15 = 519

6x = 504

x = 84

84 + 1 = 85

84 + 2 = 86

84 + 3 = 87

84 + 4 = 88

84 + 5 = 89

answer: third number in this sequence = 86

let x be the first integer, then

:

x + (x+1) + (x+2) + (x+3) + (x+4) + (x+5) = 519

:

6x + 15 = 519

:

6x = 504

:

x = 84