A cup of coffee is cooling down such that its temperature is decreasing at a constant rate of 8% per minute. Let's say the coffee starts at a temperature of 200 degrees Fahrenheit.

What's its temperature after one minute by finding 8% of 200 and then subtracting?

Question

Holloway

Mathematics

18 January, 22:28

A cup of coffee is cooling down such that its temperature is decreasing at a constant rate of 8% per minute. Let's say the coffee starts at a temperature of 200 degrees Fahrenheit.

What's its temperature after one minute by finding 8% of 200 and then subtracting?

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Answers (1)

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Camila Richard · Answer 1

Temperature after 1 minute = 184 ° F

Step-by-step explanation:

starting temperature = 200 °F

rate of decrease = 8% per minute

Temperature lost = 8% of 200 = 8/100 * 200 = 0.08 * 200 = 16 °F

It therefore means that after 1 minute, the cup of coffee loses 16 °F,

∴ Temperature after 1 minute = (starting temperature) - (lost temperature)

= 200 - 16 = 184 °F

A cup of coffee is cooling down such that its temperature is decreasing at a constant rate of 8% per minute. Let's say the coffee starts at a temperature of 200 degrees Fahrenheit.What's its temperature after one minute by finding 8% of 200 and then subtracting?

A cup of coffee is cooling down such that its temperature is decreasing at a constant rate of 8% per minute. Let's say the coffee starts at a temperature of 200 degrees Fahrenheit.

What's its temperature after one minute by finding 8% of 200 and then subtracting?