Which function forms a geometric sequence when x = 1, 2, 3, ... ?

f (x) = 8x-9

f (x) = - 2 (3/4) x

f (x) = 2/3x5

f (x) = 6-4/x

The geometric sequence is found in the relationship between consecutive terms that is constant.

In this problem, as I understand it, none of the functions forms a geometric sequence.

The functions that form a geometric sequence have the form

f (x) = h (a) ^ n where "a" is the constant relation between the successive terms.

If you wrote the function "f (x) = - 2 (3/4) x", you wanted to write instead:

f (x) = - 2 (3/4) ^ x

So that would be the function that forms a geometric sequence, where the relation between the consecutive terms is 3/4.

You can test it by dividing f (x) / f (x-1)

Then you will see that the result of that division will be 3/4.