Find the two-digit number whose tens digit is 4 less than its units digits if the original number is 2 more than 3 times the sum of the digits

Let the 2 digit number be ab remembering that ab=10a+b

a=b-4 ... equation 1

10a+b=3 (a+b) + 2 ... equation 2

take a's value in equation 1 and plug it into equation 2

10 (b-4) + b=3 (b-4) + 3b+2

5b=30

b=6 units digit

a=6-4=2 tens unit

number is 26