Two flywheels of negligible mass and different radii are bonded together and rotate about a common axis (see below). The smaller flywheel of radius 18 cm has a cord that has a pulling force of 50 N on it. What pulling force (in N) needs to be applied to the cord connecting the larger flywheel of radius 29 cm such that the combination does not rotate?

Question

Kallie Bailey

Physics

19 September, 03:27

Two flywheels of negligible mass and different radii are bonded together and rotate about a common axis (see below). The smaller flywheel of radius 18 cm has a cord that has a pulling force of 50 N on it. What pulling force (in N) needs to be applied to the cord connecting the larger flywheel of radius 29 cm such that the combination does not rotate?

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Answers (1)

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Kamila Pearson · Answer 1

Given that,

Small wheel applied force

F₁ = 50N

Small wheel radius

r₁ = 18cm

Bigger wheel radius.

r₂ = 29cm

Bigger wheel applied force

F₂ = ?

Since the combination of those forces did not cause the wheel to rotate,

Then, Στ = 0

F₁•r₁ - F₂•r₂ =

50*18 - 29F₂ = 0

900 = 29F₂

F₂ = 900 / 29

F₂ = 31.03 N

The pulling force applied at the larger wheel is 31.03N