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25 March, 11:04

A 1,200 kg car rolls down a hill with its brakes off and transmission in neutral. At one moment it is moving 5.0 m/s. A little later it is moving at 8.2 m/s. How much did its height change between the two times? Assume friction and air resistance have no effect on its motion.

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  1. 25 March, 11:06
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    The change in kinetic energy of the car is equivalent to the change in its potential energy. Thus:

    K. E = P. E

    1/2 x mΔv² = mgΔh

    h = (8.2² - 5²) / 2 (9.81)

    h = 2.15 meters
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