You decide to visit santa claus at the north pole to put in a good word about your splendid behavior throughout the year. while there, you notice that the elf sneezy, when hanging from a rope, produces a tension of 455 n in the rope.

The question here is that if sneezy hands from a similar rope while delivering presents at the earth's equator, what will be the tension in the rope be. Here is the solution:The tension on the rope when it is at pole, T = 455 NTo find, the tension, t = mgTo solve for mass, m = t/g. Substituting this we have, m=455/9.8. m=46.43 kgAssume that the downwards acceleration is, a = - 46.43 m/s^2. T = mg + maT = (46.43 kg) (9.8 m/s^2) - (46.43 kg) (-46.43 m/s^2) T = 455.01 kg-m/s^2 - - 2155.74 kg-m/s^2T = 2610.75 kg-m/s^2 = 2610.75 N