Near the surface of the moon, the distance that an object falls is a function of time. It is given by d (t) = 2.6667t2, where t is in seconds and d (t) is in feet. If an object is dropped from a certain height, find the average speed of the object from t = 1 to t = 4. (Round your answer to the nearest whole number.)

Question

Bailey Delgado

Physics

3 April, 06:08

Near the surface of the moon, the distance that an object falls is a function of time. It is given by d (t) = 2.6667t2, where t is in seconds and d (t) is in feet. If an object is dropped from a certain height, find the average speed of the object from t = 1 to t = 4. (Round your answer to the nearest whole number.)

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Answers (1)

Know the Answer?

Maci Barnes · Answer 1

averaage speed is v = 13 feet / s

Explanation:

The average speed is the ratio of the distance traveled in a given time interval, let's calculate the distance that the body travels in the two instants of time that give us

t = 1 s

d (1) = 2.6667 1²

d (1) = 2.6667 feet

t = 4 s

d (4) = 2.6667 4²

d (4) = 42.6672 feet

Let's calculate the speed

v = Δx / Δt

v = (42.6672 - 2.6667) / (4-1)

v = 40/3

v = 13.33335 feet / s

v = 13 feet / s