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4 February, 17:40

In an 8.00 km race, one runner runs at a steady 11.0 km/h and other runs at 14.8 km/h. How far from the finish line is the slower runner when the fast runner fisnishes the race?

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  1. 4 February, 18:00
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    The fast runner will cover 8 km by time = t = d/v = 8/14.8 = 0.54 hour

    at that time (0.54 hr) the slower runner would cover d = v*t = 11*.0.54 = 5.94 km

    So the slower would be at a distance = 8km - 5.94km = 2.06 km from the finish line.
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