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21 August, 09:01

A 4.33 kg cat has 41.7 J of KE How fast is the cat moving?

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  1. 21 August, 09:04
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    The answer to your question is:

    Explanation:

    Data

    mass = 4.33 kg

    E = 41.7 J

    v = ?

    Formula

    Ke = (1/2) mv²

    Clear v from the equation

    v = √2ke/m

    Substitution

    v = √2 (41.7) / 4.33

    v = 19.26 m/s Result
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