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1 July, 14:22

An ac generator with peak voltage 100 volts is placed across a 10-? resistor. What is the average power dissipated?

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  1. 1 July, 14:29
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    The correct answer is: Average Power = 500 W

    Explanation:

    Root-mean square voltage = Vrms = Vpeak / √2 = 100 / √2 volts

    Resistance = R = 10 Ω

    Average power = Pavg = (Vrms) ^2 / R = (100 * 100) / (2 * 10) = 500 W
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