A string is 9.00 m long with a mass of 7.00 g. The string is held taut with a tension of 200.00 N applied to the string. A pulse is sent down the string. How long (in ms) does it take the pulse to travel the 9.00 m of the string?

It takes the pulse 25.1 ms to travel the 9.00 m of the string

Explanation:

Force (F) = Mass (m) * Acceleration. (a)

F = ma ... equation 1

Making a the subject of equation 1 above,

a = F/m ... equation 2

Where F = T = 200 N, m = 7.00 g = 0.007 kg,

Substituting these values into equation 2,

a = 200/0.007 = 28571.43 m/s².

Using one of the equation of motion,

S = ut + 1/2at² ... equation 2

Where S = distance, u = initial velocity, t = time, a = acceleration.

u = 0.

Therefore, S = 1/2at² ... equation 3

Making t the subject of equation 3,

t = √ (2S/a) ... equation 4

Where S = 9.00 m, a = 28571.43 m/s²

Substituting this values into equation 4,

t = √{ (2*9) / 28571.43}

t = √ (18/28571.43

t = √0.00063

t = 0.0251 s

t = 25. 1 ms

Therefore it takes the pulse 25.1 ms to travel the 9.00 m of the string.