The overall reaction in the lead storage battery is: Pb (s) + PbO2 (s) + 2 H + (aq) + 2 HSO4 - (aq)  2 PbSO4 (s) + 2 H2O (l) Calculate the potential at 310 K for this battery when [H + ] = [HSO4 - ] = 4.5 M. At 310 K E o = 2.08 V for the lead storage battery. (a) 2.10 V (b) 2.24 V (c) 2.16 V (d) 2.12 V (e) not enough inf

Question

5 June, 22:45

+4

Answers (1)

Know the Answer?

Haiden Wood · Answer 1

d) 2.12 V

Explanation:

E = E° - RT/nF log 1/H⁺ x HSO₄⁻

E = 2.08 - (.059/2 X log 1/4.5x4.5)

2.08 - (-0.038) = 2.118 = 2.12 V