Ask Question
5 June, 22:45

The overall reaction in the lead storage battery is: Pb (s) + PbO2 (s) + 2 H + (aq) + 2 HSO4 - (aq)  2 PbSO4 (s) + 2 H2O (l) Calculate the potential at 310 K for this battery when [H + ] = [HSO4 - ] = 4.5 M. At 310 K E o = 2.08 V for the lead storage battery. (a) 2.10 V (b) 2.24 V (c) 2.16 V (d) 2.12 V (e) not enough inf

+4
Answers (1)
  1. 5 June, 22:49
    0
    d) 2.12 V

    Explanation:

    E = E° - RT/nF log 1/H⁺ x HSO₄⁻

    E = 2.08 - (.059/2 X log 1/4.5x4.5)

    2.08 - (-0.038) = 2.118 = 2.12 V
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “The overall reaction in the lead storage battery is: Pb (s) + PbO2 (s) + 2 H + (aq) + 2 HSO4 - (aq)  2 PbSO4 (s) + 2 H2O (l) ...” in 📗 Physics if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers