An object is moving initially with a velocity of 4.7 m/s. After 3.9 s the object's velocity is - 2.1 m/s. What is the object's average acceleration during this time?

I believe that the vf is - 2.1 m/s vi should be 4.7 m/s and the t should be 3.9s but its wrong ... ? #confused

Question

Hayden

Physics

1 October, 22:29

An object is moving initially with a velocity of 4.7 m/s. After 3.9 s the object's velocity is - 2.1 m/s. What is the object's average acceleration during this time?

I believe that the vf is - 2.1 m/s vi should be 4.7 m/s and the t should be 3.9s but its wrong ... ? #confused

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Answers (1)

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Bullet · Answer 1

Answer: The acceleration of the object is 0.67m/s^2 west.

Explanation: Here we are given the initial velocity and final velocity as well as the time taken. Acceleration is the change in velocity per unit time, thus the equation becomes.

a=dv/t

a=vf-vi/t

a=-2.1-4.7/3.9

a = 0.66m/s^2 west

An object is moving initially with a velocity of 4.7 m/s. After 3.9 s the object's velocity is - 2.1 m/s. What is the object's average acceleration during this time?I believe that the vf is - 2.1 m/s vi should be 4.7 m/s and the t should be 3.9s but its wrong ... ? #confused

An object is moving initially with a velocity of 4.7 m/s. After 3.9 s the object's velocity is - 2.1 m/s. What is the object's average acceleration during this time?

I believe that the vf is - 2.1 m/s vi should be 4.7 m/s and the t should be 3.9s but its wrong ... ? #confused