A circular room has a radius of 3.0 m. An 80 kg man stands with his back against the wall. The room then spins so the man is moving in a circle. How fast does the man have to be moving so that the normal force from the wall on his back is equal to his weight

Question

Jakobe Henry

Physics

2 March, 08:53

A circular room has a radius of 3.0 m. An 80 kg man stands with his back against the wall. The room then spins so the man is moving in a circle. How fast does the man have to be moving so that the normal force from the wall on his back is equal to his weight

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Answers (1)

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Landin Boone · Answer 1

Given:

Mass, M = 80 kg

Acceleration due to gravity, g = 9.81 m/s^2

Radius, R = 3 m

Normal force, N = M * a

= M * v/t

Centripetal force, Fc = M * v^2/R

Fc = N

a = v^2/R

v = sqrt (9.81 * 3)

= 5.425 m/s

v = w * R

w = angular velocity

w = 5.425/3

= 1.808 rad/s