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5 August, 16:03

is set into oscillatory motion with an amplitude of 23.195 cm on a spring with a spring constant of 15.2676 N/m. The mass of the bananas is 56.9816 kg. What is the maximum speed of the bananas? Answer in u

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  1. 5 August, 16:13
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    maximum speed of the bananas is 18.8183 m/s

    Explanation:

    Given data

    amplitude A = 23.195 cm

    spring constant K = 15.2676 N/m

    mass of the bananas m = 56.9816 kg

    to find out

    maximum speed of the bananas

    solution

    we know that radial oscillation frequency formula that is = √ (K/A)

    radial oscillation frequency = √ (15.2676/23.195)

    radial oscillation frequency is 0.8113125 rad/s

    so maximum speed of the bananas = radial oscillation frequency * amplitude

    maximum speed of the bananas = 0.8113125 * 23.195

    maximum speed of the bananas is 18.8183 m/s
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