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30 December, 12:44

Engine oil (η = 0.20 Pa⋅s) passes through a fine 1.90-mm-diameter tube that is 9.40cm long.

What pressure difference is needed to maintain a flow rate of 6.4mL/min?,

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  1. 30 December, 13:02
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    In this problem which involves pressure difference and flow rate, you can use the formula:

    Q = πPr^4 / (8lη)

    Where:

    Q = Flow in Liters/second

    η = Viscosity in Pa. s

    P = Pressure in pascals

    r = Radius of the tube in meters

    l = Length of the tube in meters

    The given needed to be converted to the right units for the formula.

    Q = 6.4 mL/minute or (0.0064 / 60) Liters / second

    η = 0.2 Pa. s

    r = 0.95 mm or 0.00095 m

    l = 9.40 cm or 0.094 m

    (0.0064/60) = π P (0.00095) ^4 / (8 x 0.094 x 0.2)

    The pressure difference can be found by solving for P in the equation.
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