A stone falls freely from rest for 18 s. The acceleration due to gravity is 9.8 m/s 2. What was the stone's displacement after that time? ans in m

Question

Bennett Mcintosh

Physics

7 December, 11:26

A stone falls freely from rest for 18 s. The acceleration due to gravity is 9.8 m/s 2. What was the stone's displacement after that time? ans in m

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Kamila Kramer · Answer 1

- - At the end of 18sec, the stone's velocity is (9.8m/s² x 18s) = 176.4m/s downward.

- - Starting at 0 m/s and ending at 176.4m/s, its average velocity is 88.2m/s downward.

- - Falling for 18s at an average speed of 88.2m/s, it falls (88.2m/s x 18s) = 1,587.6 m.

- - Its displacement is 1,587.6 meters downward.