2/25/20 or 2/28/20 Dispatch #53

How much power is required to carry a

35 N package a vertical distance of 18 m

if the work on the package is

accomplished in 30 s?

Students,

we you feel

Question

Quintin Cabrera

Physics

12 January, 19:48

2/25/20 or 2/28/20 Dispatch #53

How much power is required to carry a

35 N package a vertical distance of 18 m

if the work on the package is

accomplished in 30 s?

Students,

we you feel

+5

Answers (1)

Know the Answer?

Donovan Hill · Answer 1

Power = 21[W]

Explanation:

Initial dа ta:

F = 35[N]

d = 18[m]

In order to solve this problem we must remember the definition of work, which tells us that it is equal to the product of a force for a distance.

Therefore:

Work = W = F*d = 35*18 = 630 [J]

And power is defined as the amount of work performed in a time interval.

Power = Work / time

Time = t = 30[s]

Power = 630/30

Power = 21 [W]

2/25/20 or 2/28/20 Dispatch #53How much power is required to carry a35 N package a vertical distance of 18 mif the work on the package isaccomplished in 30 s?Students,we you feel

2/25/20 or 2/28/20 Dispatch #53

How much power is required to carry a

35 N package a vertical distance of 18 m

if the work on the package is

accomplished in 30 s?

Students,

we you feel