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19 June, 16:06

A 0.180 kg cube of ice (frozen water) is floating in glycerin. The glycerin is in a tall cylinder that has inside radius 5.50 cm. The level of the glycerin is well below the top of the cylinder.

A) If the ice completely melts, by what distance does the height of liquid in the cylinder change?

Express your answer with the appropriate units. Enter positive value if the surface of the water is above the original level of the glycerin before the ice melted and negative value if the surface of the water is below the original level of the glycerin.

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  1. 19 June, 16:35
    0
    0.00389 m

    Explanation:

    Archimedes principle states that the buoyant force when a body is immersed in a liquid equals the weight of the liquid displaced

    B = weight of the liquid displaced

    density is defined as the mass divided by the volume of the substance and the units is in kg/m³

    Density of glycerin = mass / volume

    ρg * volume = mass of glycerin displaced

    since the object was floating, the upthrust from the liquid equals the weight of the liquid

    ρg * volume * g = mg

    divide both side by g

    ρg * volume = 0.180 where ρg (density of glycerin) = 1260 kg / m³

    1260 * volume of glycerin displaced = 0.18 / 1260 = 0.000143 m³

    volume of glycerin displaced = πr²h₁ where h₁ = of liquid displaced

    πr²h₁ = 0.000143

    h₁ = 0.000143 / (3.142 * 0.055²) = 0.01505 m

    when the ice completely melted, it will displaces liquid equal to it own volume

    density of water = mass of water / volume

    1000 = 0.18 / v

    v = 0.18 / 1000 = 0.00018 m³

    volume = πr²h₂ where h₂ = height of the melted water

    πr²h₂ = 0.00018

    h₂ = 0.00018 / (3.142 * 0.055²) = 0.01894 m

    change in height of the liquid = h₂ - h₁ = 0.01894 m - 0.01505 m = 0.00389 m
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