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29 March, 09:04

Calculate the orbital period of a spacecraft in an orbit 300 kilometers above earth's surface

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  1. 29 March, 09:16
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    The formula that will be used to solve this question is:

    P = 2π sqrt[ a^3 / (GM) ] where:

    GM = 3.986004418 x 10^-14 m^3 sec^-2

    a = 6378000 + 300000 = 6678000 meters

    Substitute in the equation to get the period as follows:

    P = 2π sqrt [ (6678000) ^3 / (3.986004418 x 10^-14) ]

    P = 5431.0 seconds
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