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1 April, 01:09

A spring extends by. 16 meters when pulled with 20 N of Force. What is the Potential Energy in the spring at this extension?

What is the work done to extend the spring. 16 meters?

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  1. 1 April, 01:14
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    Potential energy = 1.6 J

    Work done = - 1.6 J

    Explanation:

    Potential Energy in the spring at this extension?

    The potential energy U in the spring is U = 1/2kx² where k = spring constant = F/x where F = force = 20 N and x = extension = 0.16 m. So k = 20 N/0.16 m = 125 N/m

    U = 1/2kx²

    = 1/2 * 125 N/m * (0.16 m) ²

    = 1.6 J

    What is the work done to extend the spring. 16 meters

    Work done W = U₁ - U₂ where U₁ = initial potential energy = 0 and U₂ = final potential energy = 1.6 J

    W = 0 - 1.6 J

    = - 1.6 J
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