For a rope obeying Hooke's law show that the elastic potential energy stored in the rope is given by

E=1/2kx^2

where k is the elastic spring constant and x is the extension.

Question

Troy Fritz

Physics

22 November, 04:32

For a rope obeying Hooke's law show that the elastic potential energy stored in the rope is given by

E=1/2kx^2

where k is the elastic spring constant and x is the extension.

+1

Answers (1)

Know the Answer?

Asia Summers · Answer 1

The average force can be calculated as F/2, where

F = kx

Therefore, substituting this in to the equation for energy:

Energy = Force * Distance

Energy = F/2 * x

Energy = kx/2 * x

Energy = 1/2 kx^2

For a rope obeying Hooke's law show that the elastic potential energy stored in the rope is given byE=1/2kx^2where k is the elastic spring constant and x is the extension.

For a rope obeying Hooke's law show that the elastic potential energy stored in the rope is given by

E=1/2kx^2

where k is the elastic spring constant and x is the extension.