student bikes to school by traveling first dN = 1.10 miles north, then dW = 0.300 miles west, and finally dS = 0.200 miles south.

Part A

Take the north direction as the positive y direction and east as positive x. The origin is still where the student starts biking. Let d⃗ N be the displacement vector corresponding to the first leg of the student's trip. Express d⃗ N in component form.

Question

Ernie

Physics

9 September, 04:23

student bikes to school by traveling first dN = 1.10 miles north, then dW = 0.300 miles west, and finally dS = 0.200 miles south.

Part A

Take the north direction as the positive y direction and east as positive x. The origin is still where the student starts biking. Let d⃗ N be the displacement vector corresponding to the first leg of the student's trip. Express d⃗ N in component form.

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Answers (1)

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Miah Best · Answer 1

Taking the vertical component of the displacement

1.1 - 0.2 = 0.9 mile

The horizontal component of the displacement

-0.3 mile

The magnitude of the displacement is

√[ (0.9) ² + (-0.3) ] = 0.95 mile

The direction is

θ = tan-1 (-0.3/0.9)

θ = 161.57 degrees.