You hold a bucket in one hand. in the bucket is a 500 g rock. you swing the bucket so the rock moves in a vertical circle 2.6 m in diameter. part a what is the minimum speed the rock must have at the top of the circle if it is to always stay in contact with the bottom of the bucket?

Question

Dawson Rivera

Physics

19 May, 01:22

You hold a bucket in one hand. in the bucket is a 500 g rock. you swing the bucket so the rock moves in a vertical circle 2.6 m in diameter. part a what is the minimum speed the rock must have at the top of the circle if it is to always stay in contact with the bottom of the bucket?

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Joseph Hunter · Answer 1

As the rock is the top of the circle, the aspect of the gravity comes in. So the force is F = mg; But this force must always be less than mv^2/r for it fall. mg g gr (gr) ^1/2 = > v > (9.8 * 1.3) ^ (1/2) v > 3.57 m/s So the minimum would be 3.57m/s