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15 November, 09:09

Starting at a certain speed, a bicyclist travels 200m. Suppose the bicyclist undergoes a constant acceleration of 1.20m/s squared. If the final speed is 25.0m/s, what was the bicyclists initial speed?

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  1. 15 November, 09:17
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    V2^2 = V1^2 + 2*a * s

    V2 = final velocity

    V1 = initial velocity

    a = acceleration

    s = displacement covered

    25^2 = V1^2 + 2 * 1.2 * 200

    625 = V1^2 + 480

    625 - 480 = V1^2

    145 = V1^2

    So V1 = Sqrt (145) = 12.04 m/s
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