The useful power output of the engine is 2.0 kw. Calculate the rate at which energy is absorbed from the hot reservoir.

Question

Jaydin Roman

Physics

1 June, 00:21

The useful power output of the engine is 2.0 kw. Calculate the rate at which energy is absorbed from the hot reservoir.

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Answers (1)

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Walter Osborne · Answer 1

2000 J per second or 2kJ per second.

Explanation:

The definition for power (W) is the rate of energy (J) per unit of time (seconds). In this case the power output is 2kW, or 2000W. This means the energy rate of the engine must be 2000 joules per second, or 2kJ per second.