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1 June, 01:12

In a hydraulic system, piston 1 has a surface area of 100 cm2, and piston 2 has a surface area of 900 cm2. A force of 150 N is exerted on piston 1 of the hydraulic lift. What force will be exerted on piston 2?

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  1. 1 June, 01:31
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    Since it is a hydraulic system, we will assume the pressure are equal on each piston.

    This translates to force=pressure * area, or

    P=F1/A1=F2/A2

    Solving for F2

    F2=F1 * (A2/A1) = 150N * (900/100) = 1350 N
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