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11 November, 11:01

What is the resistance in a light bulb with a voltage of 25V and a current of 0.2A

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  1. 11 November, 11:27
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    R = 125Ω

    Explanation:

    Use the equation for voltage:

    V = IR

    V is voltage, in volts V

    I is current, in amperes A

    R is resistance, in ohms Ω

    Substitute V for 25V and I for 0.2A

    V = IR

    (25V) = (0.2A) R Isolate R for resistance. Divide both sides by 0.2

    R = 125Ω

    The resistance for the lightbulb is 125 Ω.
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