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23 November, 23:28

An athlete stretches a spring an extra 28.6 cm beyond its initial length. how much energy has he transferred to the spring, if the spring constant is 52.9 n/cm?

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  1. 23 November, 23:33
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    PE = 0.5 * k * x²

    PE potential Energy

    k spring constant

    x stretch/compression of the spring
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