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29 August, 10:24

A person walks 25.0° North of East for 3.10 km. How far would she have to walk due north and due east to arrive at the same location?

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  1. 29 August, 10:51
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    Northward = R sin 25° = 3.10 sin (25) = 1.31 km Eastward = R cos 25° = 3.10. cos (25) = 2.81 km

    Explanation:

    actually in this question, you have to find out the components of a vector 25° North of east with a magnitude of 3.10 km.

    Northward = R sin 25° = 3.10 sin (25) = 1.31 km

    Eastward = R cos 25° = 3.10. cos (25) = 2.81 km
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