The nuclei of large atoms, such as uranium, with 92 protons, can be modeled as spherically symmetric spheres of charge. the radius of the uranium nucleus is approximately 7.4*10-15m. part a what is the electric field this nucleus produces just outside its surface? express your answer using two significant figures.

Total number of Photons = 92.

Radius of the Nucleus = 7.4 x 10^-15 m

Charge of the nucleus = 1.6*10^-19.

Total charge q = 92 x 1.6*10^-19 = 147.2 x 10^-19

k = 9 x 10^9 N m^2 / C^2

Electric field charge E = kq / r^2

=> E = (9 x 10^9 x 147.2 x 10^-19) / (7.4 x 10^-15) ^2

=> (1324.8 x 10^-10) / 54.76 x 10^-30 = > 24.19 x 10^20 N/C

The formula for the electric field is written below:

E = kQ/d²

where

k is the Coulomb's Law constant = 9*10⁹ N

Q is the total charge

d is the distance of the object from the center

The charge of each proton is + 1.6*10⁻¹⁹ C. So,

Q = 92 (+1.6*10⁻¹⁹ C) = 1.472*10⁻¹⁷ C

So,

E = (9*10⁹ N) (1.472*10⁻¹⁷ C) / (7.4*10 ⁻¹⁵ m) ²

E = 2.42*10²¹ N/C