On a playground, there is a merry‑go‑round. In order to get it moving, Bonnie applies a force of 41 N. The merry‑go‑round measures 7.1 m from the axis of rotation to the edge where Bonnie applies her force. Assuming she applies her force perpendicularly to a line drawn from the axis of rotation, what is the magnitude of the torque? Bonnie imparts to the merry‑go‑round?

Question

Tess Ochoa

Physics

22 September, 18:04

On a playground, there is a merry‑go‑round. In order to get it moving, Bonnie applies a force of 41 N. The merry‑go‑round measures 7.1 m from the axis of rotation to the edge where Bonnie applies her force. Assuming she applies her force perpendicularly to a line drawn from the axis of rotation, what is the magnitude of the torque? Bonnie imparts to the merry‑go‑round?

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Answers (1)

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Ibrahim Bartlett · Answer 1

291.1 Nm

Explanation:

Torque is simply the force required to cause a rotation, it is also sometimes referred to twisting force. In simple terms Torque is the rotational equivalent to the linear moment.

Calculating torque is a very simple process and is done with the following formula

T = F x d x SinФ

where

T = Toque (Nm)

F = Applied Force (N)

d = Distance from the axis of rotation (m)

Ф = Angle between F and d (Degree)

hence the torque is

T = 41 x 7.1 x Sin90

T = 291.1 Nm