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11 February, 11:01

An object, moving with constant acceleration and zero initial velocity of 129 m/s how high will it be after 4.0 s

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  1. 11 February, 11:08
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    596m

    Explanation:

    S = ut + 1/2at^2

    u = 129m/s, t = 4s and a = 10m/s^2

    S = (129*4) + 1/2 (10 * 4^2)

    S = 596m
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